x^2-140x+4500=0

Solution for x^2-140x+4500=0 equation:

x^2-140x+4500=0

a = 1; b = -140; c = +4500;
Δ = b2-4ac
Δ = -1402-4·1·4500
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-40}{2*1}=\frac{100}{2}
=50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+40}{2*1}=\frac{180}{2}
=90
$